MathsDifferential equations › Modelling with differential equations

Modelling with differential equations

Springs, dampers and linked populations all speak the same language: read the roots of an auxiliary equation and the physics falls out as oscillation, damping or decay.

Year FMEDEXCEL 9FM0 CP2

Builds on Second order equations and Forces and Newton's laws.

IN THIS TOPIC

  • Model a damped oscillator with y'' + by' + cy = 0 and interpret each term.
  • Classify light, critical and heavy damping via the discriminant b² − 4c.
  • Reduce a coupled pair of first order equations to one second order equation.

WHAT YOU PROBABLY THINK

Adding any amount of damping to an oscillator kills the oscillation outright.

Damping in three strengths

For a mass on a spring with resistance, Newton's second law gives y'' + by' + cy = 0: the y term pulls back, the y' term drains energy. The discriminant of the auxiliary equation sorts the outcomes. b² − 4c < 0 is light damping: oscillation inside a shrinking envelope, so the opening claim overstates its case. b² − 4c = 0 is critical damping, the fastest return with no overshoot; larger b is heavy damping, a slow creep home.

Light damping: y = exp(−t) cos 2t swings inside the shrinking envelope ±exp(−t)envelope ±exp(−t)y = exp(−t) cos 2tstill oscillating, always smaller
FIG. 1Light damping: y = exp(−t) cos 2t oscillates inside the envelope ±exp(−t), each swing a fixed fraction of the size of the last.

WORKED EXAMPLE

A lightly damped oscillator

Solve y'' + 2y' + 5y = 0 with y(0) = 1, y'(0) = −1.

Auxiliary: m² + 2m + 5 = 0, so m = −1 ± 2i.

General solution: y = e−t(A cos 2t + B sin 2t).

y(0) = 1 gives A = 1; differentiating and setting y'(0) = −1 gives B = 0.

y = e−tcos 2t: frequency 2 from the imaginary part, decay rate 1 from the real part.

Coupled systems

Predator and prey, or two connected tanks, arrive as a pair: dx/dt involving y, dy/dt involving x. Differentiate one equation and substitute the other, and the pair collapses to a single second order equation in one variable; solve it, then recover the second variable from the first equation.

dx/dt = y and dy/dt = −x feed each other: the pair orbit the unit circle, since x'' = −xstart (1, 0)dx/dt = ydy/dt = −xx = cos ty = −sin tclockwise orbit, radius 1
FIG. 2The coupled pair dx/dt = y, dy/dt = −x collapses to x'' = −x: each variable feeds the other's rate, and together they turn in a circle.

WORKED EXAMPLE

Collapsing a coupled pair

Solve dx/dt = y and dy/dt = −x with x(0) = 1, y(0) = 0.

Differentiate the first: x'' = dy/dt = −x, so x'' + x = 0.

Auxiliary m² + 1 = 0: x = A cos t + B sin t.

x(0) = 1 gives A = 1; y = x' = −sin t at t = 0 gives B = 0.

x = cos t, y = −sin t: the pair orbit the unit circle clockwise, for ever.

TRY IT UNSEEN

Reading the damping

A shock absorber obeys y'' + 6y' + 9y = 0. Classify the damping and give the general solution.

Show the working

Discriminant: 36 − 36 = 0, so the damping is critical.

Repeated root m = −3: y = (A + Bt)e−3t.

Critical damping is the design target for car suspension: the quickest settle with no bounce.

THE EXAM BIT

  • Interpret constants in context: the y' coefficient is resistance, the y coefficient stiffness.
  • Quote the discriminant when classifying damping; the word alone does not earn the mark.
  • In coupled systems, state which equation you differentiate and where you substitute.
  • Recover the second variable from a first order equation, never by integrating from scratch.

CHECK YOURSELF

Classify the damping in y'' + 6y' + 9y = 0 and state the long-term behaviour of any solution.

Show a hint

Compute b² − 4c and look for a repeated root.

Show the answer

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Damping is read from b² − 4c: negative oscillates in an envelope, zero settles fastest, positive creeps.

Collapse coupled pairs by differentiating one equation and substituting the other.

WORKBOOK

Printable practice for this topic: original exam-style questions with room to work, and a fully worked answer book. Free to use; please do not redistribute or sell.

CHECK YOUR PROGRESS

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  • Model a damped oscillator with y'' + by' + cy = 0 and interpret each term.
  • Classify light, critical and heavy damping via the discriminant b² − 4c.
  • Reduce a coupled pair of first order equations to one second order equation.

Open the full revision checklist to see every objective in the course in one place.

No animated video for this topic yet; these notes stand alone.