MathsFurther Pure 1 › Conic sections

Conic sections

Parabola, ellipse and hyperbola are one family: the points whose distance from a focus is a fixed multiple of their distance from a line. That multiple, the eccentricity, decides which curve appears.

Year FMEDEXCEL 9FM0 FP1

Builds on Parametric equations and Circles.

IN THIS TOPIC

  • Quote the cartesian and parametric forms of the four standard conics.
  • Compute eccentricity, foci and directrices from the curve's equation.
  • Use the focus-directrix property to solve distance problems.

WHAT YOU PROBABLY THINK

The parabola, ellipse and hyperbola are three unrelated curves that happen to share a chapter.

The standard four

Each conic comes with a cartesian equation and a parametrisation worth knowing cold. The parabola y² = 4ax is (at², 2at); the ellipse:

x2a2 + y2b2 = 1, x = a cos t, y = b sin t

the hyperbola x²/a² − y²/b² = 1 is (a sec t, b tan t) or (±a cosh t, b sinh t), and the rectangular hyperbola xy = c² is (ct, c/t). The parametric forms turn locus questions into single-variable algebra, which is why examiners lead with them.

Three conics round one focus: eccentricity 0.6 closes an ellipse, 1 balances a parabola, 1.5 opens a hyperbolafocuse = 0.6e = 1e = 1.5
FIG. 1The family portrait: parabola, ellipse and hyperbola drawn round the same focus, distinguished only by their eccentricity.

WORKED EXAMPLE

Reading an ellipse

For the ellipse x²/25 + y²/9 = 1, find the eccentricity, foci and directrices.

a = 5, b = 3, and b² = a²(1 − e²) gives 9 = 25(1 − e²), so e² = 16/25 and e = 4/5.

Foci (±ae, 0) = (±4, 0); directrices x = ±a/e = ±25/4.

Check with the point (0, 3): distances to the two foci are 5 and 5, and their sum 10 equals 2a, as it must everywhere on the ellipse.

One property, three curves

The focus-directrix property defines the whole family: distance to the focus equals e times distance to the directrix. e < 1 closes the curve into an ellipse, e = 1 balances it into a parabola, e > 1 splits it into a hyperbola's two branches. Far from being unrelated, the three curves are one definition with a dial, and the opening claim mistakes the dial's settings for different machines.

The ellipse x²/25 + y²/9 = 1 with foci (±4, 0): the two focal distances from any point always total 10(4, 0)(−4, 0)P on the curved₁ + d₂ = 2a = 10
FIG. 2The ellipse x²/25 + y²/9 = 1 with its foci at (±4, 0): from any point of the curve, the two focal distances always total 2a = 10.

WORKED EXAMPLE

A parabola's defining balance

For y² = 12x, state the focus and directrix, and verify the defining property at the point (3, 6).

4a = 12, so a = 3: focus (3, 0), directrix x = −3.

Distance from (3, 6) to the focus: 6. Distance to the directrix: 3 + 3 = 6.

Equal, as e = 1 demands: every point of a parabola sits exactly as far from the focus as from the directrix.

YOUR TURN

A hyperbola's constants

For x²/9 − y²/16 = 1, find e and the foci, and evaluate the difference of focal distances at the vertex (3, 0).

Show the working

b² = a²(e² − 1): 16 = 9(e² − 1), so e² = 25/9 and e = 5/3.

Foci (±ae, 0) = (±5, 0).

From (3, 0): distances 8 and 2, difference 6 = 2a. The constant difference of focal distances is the hyperbola's version of the ellipse's constant sum.

THE EXAM BIT

  • Learn which formula carries the minus: b² = a²(1 − e²) for the ellipse, a²(e² − 1) for the hyperbola.
  • Foci and directrices come as symmetric pairs; quoting only the positive one drops a mark.
  • For the parabola, a is read from y² = 4ax; halving 4a instead of quartering it is the standard slip.
  • Parametrise before chasing a locus; one parameter beats two coordinates.

CHECK YOURSELF

Write down parametric coordinates for a general point on y² = 8x and on xy = 9.

Show a hint

y² = 4ax has (at², 2at); xy = c² has (ct, c/t).

Show the answer

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²

=

8

x

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a

s

a

=

2

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t

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2

t

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4

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)

.

x

y

=

9

h

a

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c

=

3

:

t

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p

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(

3

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3

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.

Parabola (at², 2at); ellipse (a cos t, b sin t); hyperbola (a sec t, b tan t); rectangular hyperbola (ct, c/t).

Distance to focus = e × distance to directrix: e < 1 ellipse, e = 1 parabola, e > 1 hyperbola.

WORKBOOK

Printable practice for this topic: original exam-style questions with room to work, and a fully worked answer book. Free to use; please do not redistribute or sell.

CHECK YOUR PROGRESS

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  • Quote the cartesian and parametric forms of the four standard conics.
  • Compute eccentricity, foci and directrices from the curve's equation.
  • Use the focus-directrix property to solve distance problems.

Open the full revision checklist to see every objective in the course in one place.

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