MathsFurther Pure 2 › Arc length and surface area

Arc length and surface area

Chop a curve into tiny straight pieces and Pythagoras measures each one. Add them with an integral for length, or spin them for the area of a surface of revolution.

Year FMEDEXCEL 9FM0 FP2

Builds on Volumes of revolution and Polar curves.

IN THIS TOPIC

  • Apply the arc length formula in cartesian, parametric and polar form.
  • Compute the area of a surface of revolution as 2π times the integral of y ds.
  • Check answers against circles, cones and spheres.

WHAT YOU PROBABLY THINK

The length of a curve between two points is found by integrating y with respect to x.

Pythagoras on a small scale

Over a tiny step, the curve is near enough straight, with horizontal run dx and rise dy, so its length is √(dx² + dy²). Factoring out dx gives the cartesian formula, and factoring out dt or dθ gives the others:

s = 1 + (dydx)2 dx

Parametrically the element is √((dx/dt)² + (dy/dt)²) dt, and in polar form √(r² + (dr/dθ)²) dθ. Integrating y itself measures area under the curve, not length along it, which is where the opening claim goes astray: the square root is what turns area into distance.

One small step of a curve: run dx, rise dy, and the hypotenuse ds that the arc length integral adds updxdydsds² = dx² + dy²add the hypotenuses, not the heights
FIG. 1One small step of a curve as a right triangle: run dx, rise dy, hypotenuse ds, and the arc length integral adds the hypotenuses.

WORKED EXAMPLE

A length that comes out exactly

Find the length of y = x^(3/2) from x = 0 to x = 4.

dy/dx = (3/2)√x, so 1 + (dy/dx)² = 1 + 9x/4.

s = ∫√(1 + 9x/4) dx = (8/27)[(1 + 9x/4)^(3/2)] from 0 to 4.

= (8/27)(10^(3/2) − 1) = 9.073 to 3 decimal places. A curve chosen so the root simplifies; most do not, which is why numerical methods sit in the same option paper.

Spinning the arc

Rotate the arc about the x-axis and each element sweeps a thin band of radius y and width ds, with area 2πy ds. The surface of revolution is therefore 2π∫y ds, where ds carries the same square root as before. Rotating about the y-axis swaps the radius to x.

One arc element swept round the axis: a band of radius y and width ds, area 2πy dsydsband area 2πy dsstack the bands: 2π∫y ds
FIG. 2One arc element swept into a band: radius y, width ds, area 2πy ds, and the integral stacks the bands into a surface.

WORKED EXAMPLE

The surface of a sphere, from scratch

Find the surface area generated by rotating y = √(a² − x²) about the x-axis, from x = −a to a.

dy/dx = −x/y, so 1 + (dy/dx)² = (y² + x²)/y² = a²/y².

So ds = (a/y) dx, and the integrand 2πy ds = 2πa dx: the y cancels entirely.

Area = 2πa × 2a = 4πa², the familiar formula, derived rather than quoted. The cancellation is why bands of equal width on a sphere have equal area, whatever their latitude.

YOUR TURN

An arc that hyperbolic functions tidy

Find the length of the catenary y = cosh x from x = 0 to x = 1.

Show the working

dy/dx = sinh x, so 1 + sinh²x = cosh²x by the hyperbolic identity.

The square root is therefore just cosh x, with no surd left.

s = ∫cosh x dx from 0 to 1 = sinh 1 ≈ 1.1752. The catenary is one of the few curves whose arc length integral collapses this cleanly.

THE EXAM BIT

  • Quote the formula in the right coordinate system before differentiating anything.
  • Simplify under the square root first; most exam curves are built so a surd disappears.
  • For a surface of revolution, the radius is the distance to the axis of rotation, not always y.
  • Sense-check against a known solid: circles, cones and spheres are all fair game.

CHECK YOURSELF

A curve is given parametrically by x = 5 cos t, y = 5 sin t. Write down the integrand for its arc length, and hence its total length for 0 ≤ t ≤ 2π.

Show a hint

Differentiate both, square, add, and take the root.

Show the answer

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Arc length integrates the hypotenuse: √(1 + (dy/dx)²) dx, or the parametric and polar equivalents.

A surface of revolution is 2π∫(radius) ds, with the same ds as the arc length integral.

WORKBOOK

Printable practice for this topic: original exam-style questions with room to work, and a fully worked answer book. Free to use; please do not redistribute or sell.

CHECK YOUR PROGRESS

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  • Apply the arc length formula in cartesian, parametric and polar form.
  • Compute the area of a surface of revolution as 2π times the integral of y ds.
  • Check answers against circles, cones and spheres.

Open the full revision checklist to see every objective in the course in one place.

No animated video for this topic yet; these notes stand alone.